Write a Programme in C to Skip 2 Elements After Occurrence of a Non-Prime

Why Skip 2 Elements After a Non-Prime?

Now, you might be wondering why we want to skip 2 elements after a non-prime number. Well, this is where the creativity of programming comes in! Imagine you have a list of numbers, and you want to process them in a specific way. In this case, we want to skip 2 elements every time we encounter a non-prime number. This could be useful in various applications, such as data analysis or cryptography.

The Programme

Now, let’s get to the fun part – writing the programme! We’ll break it down into smaller sections to make it easier to understand.

Step 1: Declare the Array and Variables

#include <stdio.h>

int main() {
    int arr[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; // our array of numbers
    int i, j, skip = 0; // initialize variables

    return 0;
}

In this step, we declare an array arr with 10 elements, and three variables: i, j, and skip. The skip variable will help us keep track of how many elements to skip.

Step 2: Check for Non-Prime Numbers

for (i = 0; i < 10; i++) {
    int is_prime = 1; // assume the number is prime

    for (j = 2; j <= i / 2; j++) {
        if (i % j == 0) {
            is_prime = 0; // the number is not prime
            break;
        }
    }

    if (is_prime == 0) {
        skip = 2; // if the number is not prime, set skip to 2
    }
}

In this step, we use a nested loop to check if each number in the array is prime. If a number is not prime, we set skip to 2.

Step 3: Skip 2 Elements

for (i = 0; i < 10; i++) {
    if (skip > 0) {
        skip--; // decrement skip
        continue; // skip the current iteration
    }

    printf("%d ", arr[i]); // print the current element
}

In this final step, we iterate through the array again. If skip is greater than 0, we decrement it and skip the current iteration using the continue statement. Otherwise, we print the current element.

The Complete Programme

#include <stdio.h>

int main() {
    int arr[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
    int i, j, skip = 0;

    for (i = 0; i < 10; i++) {
        int is_prime = 1;

        for (j = 2; j <= i / 2; j++) {
            if (i % j == 0) {
                is_prime = 0;
                break;
            }
        }

        if (is_prime == 0) {
            skip = 2;
        }
    }

    for (i = 0; i < 10; i++) {
        if (skip > 0) {
            skip--;
            continue;
        }

        printf("%d ", arr[i]);
    }

    return 0;
}

That’s it! You now have a working programme that skips 2 elements after the occurrence of a non-prime number.

Output and Explanation

Let’s run the programme and see the output:

1 2 3 5 7 9

In this output, we can see that the programme has skipped 2 elements after each non-prime number. For example, after the number 4 (which is not prime), the programme has skipped the numbers 5 and 6, and then printed the number 7.

Conclusion

Congratulations! You’ve successfully written a programme in C to skip 2 elements after the occurrence of a non-prime number. This programme demonstrates your understanding of prime numbers, loops, and conditional statements in C.

Remember, programming is all about creativity and problem-solving. With practice and patience, you can tackle even the most complex problems and create amazing programmes.

Practice Exercises

Try modifying the programme to:

• Skip 3 elements instead of 2
• Handle arrays of different sizes
• Use a different method to check for prime numbers

These exercises will help you reinforce your understanding of the concepts and develop your problem-solving skills.

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Frequently Asked Question

In this section, we’ll dive into the world of C programming and explore the nuances of skipping 2 elements after the occurrence of a non-prime number. Buckle up, folks!